PSAT Math Multiple-Choice Question 667: Answer and Explanation
Question: 667
Consider the function f(x) = x2 + 2.
What operation could be performed on the right-hand side of the equation to expand the range to include negative values?
- A. Add 5
- B. Add -2
- C. Subtract 3
- D. Subtract 1
Correct Answer: C
Explanation:
(C) This function is a parabola. It opens upward because the coefficient in front of x2 is positive. (In this case, the coefficient of x2 is 1.) The function has a y-intercept of 2. Therefore, the range is [2, ∞). In order for the range to include negative numbers, the new function either needs to open downward or have a negative y-intercept. In order for it to open downward, you would multiply the right side by a negative number, but this isn't a choice.
The only choice that works is subtracting 3, which would make the y-intercept negative. The y-intercept of the new function would be -1 because 2 - 3 = -1. The range of the new function would be expanded to [-1, ∞).
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