PSAT Math Multiple-Choice Question 334: Answer and Explanation
Question: 334
If 3r + 2s = 24 and r + s = 12, what is the value of r + 6?
- A. 0
- B. 4
- C. 6
- D. 12
Correct Answer: C
Explanation:
C
Difficulty: Medium
Getting to the Answer: Since the question asks for r + 6, substitute by solving for s using the second equation, r + s = 12, so s = 12 - r. Substitute 12 - r into the first equation to get 3r + 2(12 - r) = 24. Distribute the 2 to get 3r + 24 - 2r = 24. Next, combine like terms: 3r - 2r = 24 - 24, which yields r = 0. Remember that the question asks for r + 6, not r by itself!
Choice (C) is correct.
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