PSAT Math Grid-Ins Question 92: Answer and Explanation
Question: 92
The following table shows the number of babies born in a certain hospital in October 2018. The table categorizes the births by whether the mother participated in a new prenatal program and whether the baby was below, above, or within the healthy weight range as defined by the World Health Organization.
| Below Range | Within Range | Above Range | Total | |
|---|---|---|---|---|
| Participant | 1 | 55 | 10 | 66 |
| Not a Participant | 8 | 49 | 5 | 62 |
| Total | 9 | 104 | 15 | 128 |
The hospital decides to focus its study on the two at-risk groups with the highest number of babies: Not a Participant/Below Range and Participant/Above Range. If a baby is randomly selected from all those born at this hospital in October 2018, what is the probability that the baby belongs to one of those two groups?
Correct Answer: 9/64 or .141
Explanation:
9/64 or .141
Difficulty: Medium
Category: Probability
Getting to the Answer: From the table, the numbers for Not a Participant/Below Range and Participant/Above Range are 8 and 10, respectively, with a total of 8 + 10 = 18. There were 128 babies born in the hospital in October 2018, so the probability of randomly selecting one from the two specified groups is 
. You could also grid this as .141.
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