Digital PSAT Math Practice Question 282: Answer and Explanation
Question: 282
What is the smallest possible value for x in this inequality?
-2x + 3 ≤ -5
- A. 4
- B. 1
- C. 0
- D. -6
Correct Answer: A
Explanation:
(A) Solve inequalities just like any other equation, but remember to flip the sign of the inequality any time you multiply or divide by a negative number. The first step is to subtract 3 from both sides so that all of the constants are on the right and all of the variables are on the left:
- 2x ≤ - 8
Next, you have to divide by - 2, remembering to flip your inequality since it is a negative number: x ≥ 4. Because x must be greater than or equal to 4, it must be at least 4. Therefore, the correct choice is choice (A).
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